-7(x^2+2)-(3x+1)=0

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Solution for -7(x^2+2)-(3x+1)=0 equation: 



-7(x^2+2)-(3x+1)=0

We multiply parentheses

-7x^2-(3x+1)-14=0

We get rid of parentheses

-7x^2-3x-1-14=0

We add all the numbers together, and all the variables

-7x^2-3x-15=0

a = -7; b = -3; c = -15;
Δ = b2-4ac
Δ = -32-4·(-7)·(-15)
Δ = -411
Delta is less than zero, so there is no solution for the equation

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